WebYes; If two vertices (of a triangle inscribed within a circle) are opposite each other, they lie on the diameter. By the inscribed angle theorem, the angle opposite the arc determined by the diameter (whose measure is 180) has a measure of 90, making it a right triangle. Good job! :] [ ( 4 votes) Celine 10 years ago At 1:20 Web29 mrt. 2024 · Let ABC with right angle at B. AC will be hypotenuse, AC = 13 cm And AB = 12 cm, BC = 5 cm We revolve ABC about the side AB (= 12 cm) , we get a cone as shown in the figure. Radius = r = 5 cm, & Height = h = 12 cm Volume of solid so obtained = 1/3 r2h = (1/3 " " 5 5 12) cm3 = (1 " " 25 4) cm3 = 100 cm3 .
ABC is a right triangle with AB = AC. If bisector of ∠ A ... - Byju
WebABC is a right triangle right−angled at C. Let BC=a, CA=b, AB=c and let p be the length of perpendicular from C on AB, prove that cp=ab 1/p^2 =1/a^2 +1/b^2 . WebIf we consider the right angle, the side opposite is also the hypotenuse. So sin (90)=h/h=1. By pythagorean theorem, we get that sin^2 (90)+cos^2 (90)=1. So, substituting, 1+cos^2 (90)=1 cos^2 (90)=0 cos (90)=0 And we see that tan (90)=sin (90)/cos (90)=1/0. … radioaktive bananen
[Solved] Consider the following statements: 1. If ABC is a right-ang
Web7 feb. 2024 · ABC is a triangle right angled at B. Let M and N be two points on AB such that AM = MN = NB. Let P and Q be two points on AC such that PM is parallel to QN and … WebIn ABC , B is the right angle and BD is perpendicular to AC, then: A BC2 =AC×DC B BC2 =AD× AC C BC2 =BD×AC D BC2 =DC2+AD2 Solution The correct option is A BC2 = AC×DC In ABC and BDC ∠ABC= ∠BDC =90∘ ∠C = ∠C (common angle) Therefore, ABC ∼ BDC [by AA similarity] BC DC = AC BC BC2 = AC×DC Suggest Corrections 3 Similar … Web11 nov. 2024 · Consider right triangle ABC, right-angled at B. If AC = 17 units and BC = 8 units determine all the trigonometric ratios of angle C. Solution: In triangle ABC, Use Pythagoras triplet . AB 2 = AC 2 – BC 2. AB =√17 2 – 8 2. AB = … dp31517c brake pads